The effective speed of the student while going upstream (i.e , the velocity of the student with respect to the river ) is 0.75 m/s whereas the same while returning downstream is 1.45 m/s .
So , total time taken = 1000/0.75 + 1000/1.45 = 2023 seconds = 33 minutes 43 seconds .
If he were swimming in still water , then this time would be = 2000/1.1 = 30 minutes 18 seconds .
Thus the trip would be shorter by 3 min 25 sec .
A river has a steady speed of 0.470 m/s. A student swims upstream a distance of 1.00 km and swims back to the starting point
1 answer
1 answer