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A right triangle and a square share a side. The hypotenuse of the triangle measures 10 cm. One base of the triangle measures 4 cm. Neither the known base nor the hypotenuse is the side that is shared with the square. Find the area of the square.

2 answers

Given triangle ABC, the right angle being at B.
Given AC = 10
Given AB = 4
Neither AB nor AC share the side of the square.
Therefore, BC = the side of the square being BC = sqrt(10^2 - 4^2) = 9.1651 making the area of the square 84 sq.cm.
I have a triangle with the base of 11 and all the sides look about the same but i don't know how to find out the height?
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