A right pyramid on a base10m square is 15m high find the volume of the pyramid if the top 6m of the pyramid are removed what is the volume of the remaining frustum

Answer 1

volume = 1/3 * area of base * height

vol top 6 m = 1/3 * [(6/15) * 10]^2 * 6

Answer 2

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Answer 3

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Answer 4

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