1a. A right pyramid on a base 10cm square is 15cm high. Find the volume of the pyramid

b. If the top of the pyramid are removed, what is the volume of the remaining frustum

1 answer

a. To find the volume of the pyramid, we can use the formula V = (1/3) * base area * height.

The base area in this case is a square with side length 10cm, so the base area is 10 * 10 = 100cm^2.

Plugging in the values, we get V = (1/3) * 100 * 15 = 500 cm^3.

Therefore, the volume of the pyramid is 500 cm^3.

b. To find the volume of the frustum, we need to find the volume of the large pyramid (before the top is removed) and subtract the volume of the small pyramid (the top that is removed).

The volume of the large pyramid is 500 cm^3, as calculated in part a.

To find the volume of the small pyramid, we need to find the height of the small pyramid. Since the large pyramid is 15cm high and the small pyramid has the top removed, its height is 15cm - 10cm = 5cm.

Using the same formula as before, V = (1/3) * 100 * 5 = 166.67 cm^3.

Therefore, the volume of the frustum is 500 cm^3 - 166.67 cm^3 = 333.33 cm^3.