A rifle aimed horizontally at a target fired a bullet which lands 2 cm below the aim point. If the rifle was 25 m away find a) the flight time and b) the velocity with which the bullet left the rifle.
I would first have to convert the 2 cm into m but what would be the equations i would use?
I will be happy to critique your work: the time of flight can be found by the distance it fell.
to find the time would I use
t = sqrt((2*h)/g))
I got sqrt(2(.02m)/9.8)
which equals .0638 seconds
for the velocity would i use
v= v initial + at where v intial is 0
v= (9.8)(.0638s) which equlas .625 m/s
did i do this correctly?
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