A researcher found a sample proportion of 0.94 for estimating the population proportion of freshmen at a university who had Facebook accounts. If the standard deviation of the sampling distribution of the sampling proportion is 0.02, what is a 95% confidence interval for the population proportion?

Answer 1

Formula with your data:

CI95 = 0.94 ± 1.96(0.02)

Note: ± 1.96 represents 95% confidence interval using a z-table.

I let you take it from here to calculate the interval.