A research submarine is designed to operate 3 km below the ocean surface. If then interior pressure is 1 atm, what is the total pressure on a 15cm diameter window and force on window.

Question

The average density of seawater is 1028 kg/m3

Answer 1

pressure above=weightwater+weightatmosphere
=density*height+1atm
=1028kg/m^3*g*3000m + 1atm
figure that out.

then, pressure on glass is above -1atm, so force on glass is that pressure times area, or area= pi r^2=PI*.075^2