A submarine is at a depth of 15.0 m under the ocean surface. The inside of the submarine is kept at atmospheric pressure. What is the net force being exerted on a circular window of the submarine that has a radius of 25 cm? The density of the ocean water is 1030 kg/m3.

Question

A submarine is at a depth of 15.0 m under the ocean surface. The inside of the submarine is kept at atmospheric pressure. What is the net force being exerted on a circular window of the submarine that has a radius of 25 cm? The density of the ocean water is 1030 kg/m3.
I know that the direction of the net force is being exerted into the submarine but I don't know how to calculate it..
Thank you!

bobpursley · Answer

net force=(outside pressure-1atm)areawindow

so, the pressure of the water weight from above is...

P= weightwater/area + atmospheric pressure above
= g*density*heigh*area/area+ 1atm
= g*density*15m + 1atm
= 9.8*15*1030 + 101.3kpa