A rescue plane spots a person floating in a lifeboat 55 m directly below and releases an emergency kit with a parachute. The package descends with a constant vertical acceleration of 6.91 m/s. If the horizontal speed of the plane was 70.6 m/s, how far is the package from the lifeboat when it hits the waves?

Question

225 m

1.27 km

323 m

282 m

Answer 1

vertical acceleration of 6.91 m/s>>> I bet the writer mean vertical velocity.
calcualte time in air; height/speedabove
then, horizontal distance: time in air*initial horizontal veloicty

Answer 2

Would it be 282 m?

Answer 3

55/6.91 = 7.96
7.96 * 70.6 = 562

That is not one of the listed answers. I suspect using acceleration of 6.91 m/s^2 works better.

Answer 4

Somehow my answer did not appear
55 = (1/2) 6.91 t^2
t = about 4
4 * 71 = 284
yes, 282

Answer 5

Thank you!