A rescue plane is flying horizontally at a height of 132 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of -6.89 m/s^2 and the initial plane horizontal speed is 68.9 m/s. Assuming air resistance and wind are negligible, how long will the emergency kit be falling through the air?

asked by alex

6 years ago

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1 answer

distance = 1/2 * acceleration * time^2

-132 = 1/2 * -6.89 * t^2

answered by scott

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Question

A rescue plane is flying horizontally at a height of 132 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of -6.89 m/s^2 and the initial plane horizontal speed is 68.9 m/s. Assuming air resistance and wind are negligible, how long will the emergency kit be falling through the air?

1 answer

distance = 1/2 * acceleration * time^2

-132 = 1/2 * -6.89 * t^2

Ask a New Question or answer this question.

scott · Answer

distance = 1/2 * acceleration * time^2 -132 = 1/2 * -6.89 * t^2