ℰ=-dΦ/dt=-d( BAcosα )/dt
cosα=1
ℰ =BA/t= Bab/t=Bb(a/t)=Bbv=
=0.125•0.045•4.3=0.024 V
A rectangular wire loop of dimensions a×b, with a=3.5 cm and b=4.5 cm, is pulled parallel to side a at a constant speed v=4.3 m/sec into a region where the magnetic field, |B|=0.125 T, is uniform and perpendicular to the loop. The loop enters the magnetic field at time t=0.
(a) Calculate the rate at which the magnetic flux through the loop is changing. Express your answer in Tesla m2/sec.
(b) What is the magnitude of the induced EMF at time t?
3 answers
what is the rate? ._.
both a) and b) are 0.024
3 answers