A rectangular garden dimensions 30m by 20m and is divided into 4 parts by two pathways that run perpendicular from its side. One pathways has a width 8dm and 7dm. What is the total useble area of the garden?
2 answers
50m
50m is the total length of the paths, but that was not the question.
30m*20m = 600m^2
you don't say which path runs the length and which the width. If the wider path is the longer, then the area used up by the paths is
.8*30 + .7*20 - .8*.7 = 37.44
So, that leaves 600-37.44 = 562.56 m^2 for the garden.
If the wider path is the shorter one, then change the numbers accordingly.
30m*20m = 600m^2
you don't say which path runs the length and which the width. If the wider path is the longer, then the area used up by the paths is
.8*30 + .7*20 - .8*.7 = 37.44
So, that leaves 600-37.44 = 562.56 m^2 for the garden.
If the wider path is the shorter one, then change the numbers accordingly.
1 answer