Asked by Usman
A rectangular garden is to be fenced off and divided into 3 equal regions by fencing parallel to one side of the garden. 200 feet of fencing is used. find the dimensions of the garden that maximizes the total area enclosed. what is the maximum area?
Answers
Answered by
bobpursley
area= LxW
fencing:200=2L+2W+2L
200=4L+2W check that.
area= LW=L(100-50L)
darea/dL=(100-50L)+ L(-50)=0
-100L=-100
L=1
W=100-2L=100-2=98
fencing:200=2L+2W+2L
200=4L+2W check that.
area= LW=L(100-50L)
darea/dL=(100-50L)+ L(-50)=0
-100L=-100
L=1
W=100-2L=100-2=98
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