A rectangular field whose length is 33 less than four times its width needs to be enclosed with exactly 104 meters of fencing.
What are the dimensions of the field?
2 answers
2(x + 4x-33) = 104
104=2L+2W=2(4W-33)+2W
104=10W-66
10W=170
W=17m
L=68-33=35
104=10W-66
10W=170
W=17m
L=68-33=35