a rectangular field is 15m long and 10m wide the otherrectangular field having same perimetre has its sides in the ratio 4:5 find the dimension of the second field

Answer 1

P1 = 2L + 2W = 2*15 + 2*10 = 50 M. = P2.

W/L = 4/5. W = 0.8L.

P2 = 2W + 2L.
P2 = 2*0.8L + 2L,
50 = 1.6L + 2L, L = 13.9 M.

W = 0.8L = 0.8*13.9 = 11.1 m.