A rectangular field has a total perimeter of 128 feet. The width is 24 feet less than the length.

What are the dimensions of the field?

3 answers

L = W + 24

2L + 2W = 128

Substitute W + 24 for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.

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