how are the 6 fields to be arranged?
2x3:
9x+8y = 1200
a = 6xy = 6x(1200-9x)/8
max area at x = 200/3
1x6:
12x+7y = 1200
a = 6xy = 6x(1200-12x)/7
max area at x = 50
Note that the fencing is divided equally among lengths and widths.
A rectangular field is to be subdivided in 6 equal fields. There is 1200 feet of fencing available.
Find the dimensions of the field that maximizes the total area. (List the longer side first)
Width = feet
Length = feet
What is the maximum area ? Area =
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