a rectangular box is 12 in x 14 in x 18 in. what is the surface area of the largest size sphere that could fit in this box leave your answer in terms of pi

1 answer

To find the surface area of the largest sphere that can fit inside a rectangular box, we first need to determine the diameter of that sphere. The largest sphere that can fit inside the box will have a diameter equal to the smallest dimension of the box.

The dimensions of the box are:

  • Length: 18 inches
  • Width: 14 inches
  • Height: 12 inches

The smallest dimension is 12 inches, meaning the diameter of the largest sphere that can fit in the box is also 12 inches. Therefore, the radius \( r \) of the sphere is half of the diameter:

\[ r = \frac{12}{2} = 6 \text{ inches} \]

Next, we can use the formula for the surface area \( A \) of a sphere:

\[ A = 4\pi r^2 \]

Substituting in the radius:

\[ A = 4\pi (6)^2 \]

Calculating \( (6)^2 \):

\[ (6)^2 = 36 \]

Now substituting this back into the area formula:

\[ A = 4\pi \times 36 = 144\pi \]

Thus, the surface area of the largest sphere that could fit in the box is

\[ \boxed{144\pi} \text{ square inches.} \]