a = xy = xe^(-3x)
da/dx = (1-3x)e^(-3x)
so, where is da/dx = 0?
A rectangle has one side on the x-axis, one side on the y-axis, one vertex at the orgin ans one on the curve y = e^-3x , for x>(equal) 0. find the maximum area (using calculus)
3 answers
is the answer 3?
no.
e^(-3x) is never zero, so where is (1-3x)=0?
x = 1/3
so, a = (1/3)e^(-3*1/3) = 1/(3e)
don't forget your Algebra I now that you're in Calculus!
e^(-3x) is never zero, so where is (1-3x)=0?
x = 1/3
so, a = (1/3)e^(-3*1/3) = 1/(3e)
don't forget your Algebra I now that you're in Calculus!