A recreational court is twice as long as it is wide. If the perimeter is 153 ft, find the dimensions of the court.

Answer 1

Let's assume the width of the recreational court is x feet.

Since the length is twice as long as the width, the length would be 2x feet.

The perimeter of a rectangle is calculated by adding the lengths of all four sides. Therefore, the perimeter of the recreational court can be expressed as:

Perimeter = 2(length + width)
153 = 2(2x + x)

Simplifying the equation, we have:
153 = 2(3x)
153 = 6x

Divide both sides of the equation by 6:
153/6 = x
25.5 = x

Therefore, the width of the recreational court is 25.5 feet.

The length of the court is twice the width, so:
Length = 2x = 2(25.5) = 51 feet.

Therefore, the dimensions of the recreational court are 25.5 feet by 51 feet.