A recreational court is three times as long as it is wide. If the perimeter is 272 ft, find the dimensions of the court.

1 answer

Let the width of the recreational court be \( x \) feet. Since the length is three times the width, the length can be expressed as \( 3x \) feet.

The formula for the perimeter \( P \) of a rectangle is given by:

\[ P = 2(\text{length} + \text{width}) \]

Substituting the expressions for length and width into the perimeter formula, we have:

\[ 272 = 2(3x + x) \]

Simplifying the expression inside the parentheses:

\[ 272 = 2(4x) \]

This can be further simplified:

\[ 272 = 8x \]

Now, we solve for \( x \) by dividing both sides by 8:

\[ x = \frac{272}{8} = 34 \]

Thus, the width of the court is \( 34 \) feet. Now we can find the length:

\[ \text{length} = 3x = 3 \times 34 = 102 \text{ feet} \]

So, the dimensions of the court are:

  • Width = \( 34 \) feet
  • Length = \( 102 \) feet

To verify, we can check the perimeter:

\[ P = 2(\text{length} + \text{width}) = 2(102 + 34) = 2(136) = 272 \text{ feet} \]

Everything checks out, so the final dimensions of the court are:

\[ \text{Width} = 34 \text{ feet}, \quad \text{Length} = 102 \text{ feet} \]