A reaction of the form aA-----products is second-order with a rate constant of 0.225 L/(mol/s). If the initial concentration of A is 0.293 mol/L, what is the molar concentration of A after 35.6 secs?

Answer 1

(1/A) - (1/Ao) = akt
solve for A.

Answer 2

1/[A] =kt+1/[A]0
=(0.225)(35.6)+(1/0.293)
1/[A]=11.42
[A]=0.088mo.l