2X + Y = X2Y
rate = (X)^2(Y)
What if (X) = 1 and (Y) = 1
then rate = (1)^2(1) = 1
Now we double X and triple y so
rate = (2)^2(3) = 12
So you have changed it from rate of 1 to rate of 12. What factor is that.
A reaction in which X and Y form products was found to be second order in X and first order in Y. By what factor will the rate of the reaction change if [X] is doubled and [Y] is tripled?
a. 10
b. 12
c. 20
d. 2
2 answers
Oh I see, so it's 12. Thank you!!
1 answer