If this is for distribution of means,
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
A random sample of size 36 is taken from a population with mean 50 and standard deviation 5. Find P( < 51.5).
2 answers
.9641