If a rectangular array,
6x+6y = 750
a = 4xy = 4x(750-6x)/6 = 500x - 4x^2
max area at x = 62.5, y=62.5, large pen = 125x125
If a linear array,
8x+5y = 750
a = 4xy = 4x(750-8x)/5 = 600x - 32/5 x^2
max area at x=46 7/8, y=75, large pen = 186.5x75
As usual, the square provides the largest area.
As usual, in either case, the fence is evenly divided among lengths and widths.
A rancher with 750ft of fencing wants to enclose a large rectangle area and then divide it into four equal-sized pens to hold animals. If the maximum area is desired to ensure humane treatment of the anima, what should be the dimensions of the larger rectangle. What should be the dimensions for each of the smaller holding pens?
3 answers
the average of five numbers is 16. Suppose 10 is added to five numbers. What is the average of the six numbers?
Do not tag a new question at the end of somebody else's question.
It will appear to be a reply to that problem
Yours:
The sum so far is 80
after adding 10 the new sum is 90
avg of those 6 numbers = 90/6 = 15
It will appear to be a reply to that problem
Yours:
The sum so far is 80
after adding 10 the new sum is 90
avg of those 6 numbers = 90/6 = 15
1 answer