sin A = 1.2m/20m = 0.06
A = 3.44o
Fap-Fp = m*a = m*0 = 0
300 - Fp = 0
Fp = 300 N = Force parallel to the ramp.
Fp = mg*sin A = 300 N.
m * 9.8*sin3.44 = 300
0.588m = 300
m = 510.2 kg. = Combined mass.
A ramp 20m long slopes down 1.2m to the edge of a lake. A force of 300N is needed to pull a boat on a trailer at constant speed up the ramp when they are clear of the water. If friction is negligible, what is the combined mass of the boat and trailer.
Hints: Calculate MA of inclined plane. Then use definition of MA= Force Out/ Force in
3 answers
Wrong...
MA of inclined plane = 20m/1.2m = 16.67
&the rest idk.
MA of inclined plane = 20m/1.2m = 16.67
&the rest idk.
In the above procedure, m*a means mass*
acceleration.
MA = 20/1.2 = 16.67=Mechanical advantage
MA = Fo/Fin = 16.67
Fo/300 = 16.67
Fo = 16.67 * 300 = 5,000 N. = Output.
m*g = 5000
m * 9.8 = 5000
m = 510.2 kg. = Combined mass.
acceleration.
MA = 20/1.2 = 16.67=Mechanical advantage
MA = Fo/Fin = 16.67
Fo/300 = 16.67
Fo = 16.67 * 300 = 5,000 N. = Output.
m*g = 5000
m * 9.8 = 5000
m = 510.2 kg. = Combined mass.