conserve momentum. So,
2.33*10^4 * 3.71 + 4.66*10^4 * 1.44 = 6.99*10^4 * v
v = 2.20 m/s
So, now just figure
KE = 1/2 mv^2
for each car before, and the combo car after the collision.
A railroad car with a mass of 2.33 × 104 kg moving at 3.71 m/s collides and joins with two railroad cars already joined together, each with the same mass as the single car and initially moving in the same direction at 1.44 m/s.
a) What is the final speed of the three joined cars after the collision?
Answer in units of m/s.
011 (part 2 of 2) 10.0 points
b) What is the decrease in kinetic energy during the collision?
2 answers
2.20 m/s