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A quartz sphere is 14.0 cm in diameter. What will be its change in volume if its temperature is increased by 305 °F? (the coefficient of volume expansion of quartz is (1.50 × 10^-6) °C-1) Answer in cm^3

I tried this twice and got 0.657 cm^3 and 0.18cm^3 but they are both incorrect. Is my third attempt correct?

(100/180) change in C = 1 change in F
305 change in F = 305*(100/180) C = 169.4 change in C

delta V = V1*gamma*dT
= (4/3)*pi*(d/2)^3*gamma*dT
= (4/3)*pi*(0.14/2)^3*1.5*10^-6*169.4
= 0.3650794557

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