A purse contains 4 pennies, 2 nickels, I dime, and I quarter. Different values can be obtained by using one or more coins in the purse. How many different values can be obtained?
6 answers
4^2^1^1 = 16 values
Start listing them. Using the quarter, there are
q
qd, qnn
qdnn
qdp, qnnp
qdpp, qnnpp
and so on.
Now eliminate the quarter, and you get another list using the dime...
Lots more than 16 values.
q
qd, qnn
qdnn
qdp, qnnp
qdpp, qnnpp
and so on.
Now eliminate the quarter, and you get another list using the dime...
Lots more than 16 values.
Thank you. I just wanted to know if there was a faster way to do it.
Talha You are way off. That is a bad solution. If you list them then you will get way more than 16. You are a big noob. ;0 :0 :0 :P
The answer is 49, this is a simple combinations problem.
how did you get that
1 answer