A punter in a football game kicks a ball from the goal line at 60° from the horizontal at 25 m/s. How far down field does the ball land?

Answer 1

the equation of motion for an object thrown from (0,0) at an angle θ with velocity v is

y(x) = -g/(2v^2 cos^2 θ) x^2 + xtanθ

the range (where y=0 again) is

r = v^2 sin2θ/g

the maximum height reached is

h = v^2 sin^2 θ/2g

So, we have
θ = 60°
v = 25

r = 25^2 * sin 120°/9.8
= 625 * 0.866 / 9.8
= 55.2m