F=qvB =evB
v=F/eB=...
A proton moves perpendicularly to a magnetic field that has a magnitude of 1.22×10−2
T.
The charge on a proton is 1.60×10−19 C.
What is the speed of the particle if the
magnitude of the magnetic force on it is 4.79×
10−14N?
Answer in units of m/s
1 answer