A proton moves perpendicularly to a magnetic field that has a magnitude of 1.22×10−2

T.
The charge on a proton is 1.60×10−19 C.
What is the speed of the particle if the
magnitude of the magnetic force on it is 4.79×
10−14N?
Answer in units of m/s

1 answer

F=qvB =evB
v=F/eB=...
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