please check my answer

An electron moves north at a velocity of 9.8 * 10^4 m/s and has a magnetic force of 5.6 * 10^-18 N west exerted on it. If the magnetic field points upward, what is the magnitude of the magnetic field?

F=BqV
F= 5.6 * 10^-18N
q= 16 * 10^-19C
V= 9.8 * 10^4 m/s
B= ?
B= F/qV = 5.6 * 10^-18/ 1.6 * 10^-19 * 9.8 * 10^4

= 3.57 * 10^-4 T

is this correct?

2 answers

correct

234

Ask a New Question or answer this question.

Similar Questions

An electron with a speed of 3.00X10^6 m/s moves into a uniform electric field of magnitude 1.00X10^3 N/C. Thefield lines are
1. 1 answer
A pet-store supply truck moves at 25.0 m/ north along a highway. Inside, a dog moves at 1.75 m/s at an angle of 35.0 degrees
1. 3 answers
A car makes a 60-km trip with an average velocity of 38.5-km/h in a direction due north. The trip consists of three parts. The
1. 1 answer
A boat moves with a velocity of 15m/s north in a river, which flows with a velocity of 8m/ s west. Calculate the boat resistant
1. 3 answers