A projectile is launched at ground level with an initial speed of 56.0 m/s at an angle of 35.0° above the horizontal. It strikes a target above the ground 2.90 seconds later. What are the x and y distances from where the projectile was launched to where it lands?

Answer 1

Vo = 56m/s[35o].
Xo = 56*Cos35 = 45.9 m/s.
Yo = 56*sin35 = 32.1 m/s.

Y = Yo*t + 0.5g*t^2=32.1*2.9 -4.9*2.9^2
= 52 m.

X = Xo*T = 45.9m/s * 2.9s = 133 m.