What is the maximum height above ground a projectile of mass 0.67 kg, launched from ground level, can achieve if you are able to give it an initial speed of 78.5 m/s?

Answer 1

V^2 = Vo^2 + 2g*h
V = 0
Vo = 78.5 m/s.
g = -9.8 m/s^2.
Solve for h.