A projectile is fired with an initial speed of 32.5 m/s at an angle of 61.4° above the horizontal. The object hits the ground 7.55 s later. What is the absolute value of the difference in height between the launch point and the point where the projectile hits the ground?

Answer 1

the vertical point of the projectile at any time t is

h(t)=32.5Sin61.4 * t - 4.9 t^2