a projectile is fired from the surface of the earth with a speed of 200 m/s at an angle of 30 degrees above the horizontal. If the ground is level, what is the maximum height reached by the projectile

Answer 1

h = V^2(sin^2(30))/2g

Answer 2

Vy= sin30(200)=100m/s

t=(Vf-Vi)/a, t=(0-100)/9.81, t=10.3s

Sy=Vy(t), Sy= 100(10.3), Sy= 1019m

Answer 3

1019M

Answer 4

509.7M