A police car stopped at a set of lights has a speeder pass it at 100 km/h. If the police car can accelerate at 3.6 m/s^2, how long does it take to catch the speeder?

Answer 1

They to the same distance in the same time.
d=100km/hr*t
d=1/2 3.6m/s^2 t

change km/hr to m/s in the first equation, then set d=d, and solve for t.

Answer 2

Why do you multiply by 1/2?