To find the electric field produced at x = 25.0 cm² by a point charge q = 400x10^(-9) C at the origin, you can use Coulomb's law.
Coulomb's law equation states that the electric field (E) produced by a point charge (q) at a distance (r) from the charge is given by:
E = k * (q / r^2),
where k is the electrostatic constant and is equal to 9 * 10^9 Nm^2/C^2.
In this case, the distance (r) is 25.0 cm = 0.25 m.
Substituting the given values into the equation, we have:
E = (9 * 10^9 Nm^2/C^2) * (400 * 10^(-9) C) / (0.25 m)^2.
Simplifying the equation:
E = (9 * 400) / (0.25)^2 * 10^9 N/C.
E = (3600 / 0.0625) * 10^9 N/C.
E = 57600 * 10^9 N/C.
Therefore, the electric field produced at x = 25.0 cm² is 5.76 x 10^14 N/C.
A point charge, q= 400x 10^-9 C, is placed on the x-axis at the origin. What is the electric field produced at x = 25.0 cm²
in simple steps
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