To find the electric field produced by a point charge, you can use Coulomb's law equation:
E = k * (q / r^2)
where:
E is the electric field
k is the electrostatic constant, approximately equal to 9 x 10^9 Nm^2/C^2
q is the charge
r is the distance from the charge
In this case, the charge q is given as 400 x 10 C, which is equal to 400 Coulombs.
The distance r is given as 25.0 cm, which is equal to 0.25 meters.
Plugging these values into the equation, we have:
E = (9 x 10^9 Nm^2/C^2) * (400 C / (0.25 m)^2)
Simplifying the equation:
E = (9 x 10^9 Nm^2/C^2) * (400 C / 0.0625 m^2)
E = (9 x 10^9 Nm^2/C^2) * (6400 C / m^2)
E = (9 x 10^9 N * 6400) / Cm
E = 57.6 x 10^9 N/C
Therefore, the electric field produced at x = 25.0 cm^2 is 57.6 x 10^9 N/C.
A point charge, q= 400x 10 C, is placed on the x-axis at the origin. What is the electric field produced at x = 25.0 cm²
in simple steps
1 answer