A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. How much did the hockey puck accelerate? How much force was exerted on the puck? How much force did the puck exert on the hockey stick?

Answer 1

Assuming the puck was stationary to begin with and experiences constant acceleration, vf=vi+a*t
rearrange to isolate for a, you get
a=(vf-vi)/t
but the initial velocity was zero, so
a=vf/t

once you know a,
F=m*a

Newton's Third says for every action there is a reaction, so whatever force the stick exerts on the puck, the force exerted on the stick by the puck is of equal magnitude

Answer 2

what are your name

Answer 3

The puck accelerated 6m/s in 2s, which (assuming constant acceleration) is 3m/s^2

f = m*a
f = 0.200kg * 3m/s^2 = 0.6N
From Newton's Third Law,
there was 0.6N exerted both on the puck by the stick, and 0.6N on the stick by the puck