A player strikes a hockey puck giving it a velocity of 47.673 m/s. The puck slides across the ice for 0.175 s after which time its velocity is 46.473 m/s.

Question

A player strikes a hockey puck giving it a velocity of 47.673 m/s. The puck slides across the ice for 0.175 s after which time its velocity is 46.473 m/s.
The acceleration of gravity is 9.8 m/s2 . The mass of the puck is 185 g.

If the puck strikes the goalie’s pads and stops
in a distance of 4.39 cm, what average force is
exerted on the pads?
Answer in units of N.

bobpursley · Answer

I wonder what the velocity of the puck was at the initial contact with the pad? If you assume it is 46.473m/s, then 46.473^2=2(force/masspuck)*.0439 and you solve for force (mass is in kg)