V = 155mi/h @ 225o + 45mi/h @ 0o.
X = 155*cos225 + 45 = -64.6 Mi/h.
Y = 155*sin225 = -109.6 Mi/h.
V^2 = X^2 + Y^2.
V^2 = (-64.6)^2 + (-109.6)^2 = 16,185.66
V = 127.2 Mi/h.
A plane is flying southwest at 155 mi/h and encounters a wind from the west at 45.0 mi/h. What is the plane's velocity in respect to the ground in standard position?
I know the answer, but can't figure out how to get the answer. Any help would be appreciated!
1 answer
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