v=sqrt{v(p)²+v(w)²-2v(p)v(w)cos α}=
=sqrt{100²+30²-2•100•30cos45} =81.6 km/h
s= vt=81.6•3=244.8 km
β= 85° (northeast)
A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point? Show your work.
1 answer