A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point? Show your work.

Answer 1

V = 100km/h[90o] + 30km/h[315o]

X = 100*cos90 + 30*cos315 = 21.21 km/h
Y = 100*sin90 + 30*sin315 = 78.79 km/h

tan A = Y/X = 78.79/21.21 = 3.71461
A = 74.93o

V=Y/sinA = 78.79/sin74.93=81.6 km/h
[78.79]
D=V*t = 81.6[78.79] * 3 = 245 km[78.8o]

Answer 2

CORRECTION:
V = 81.6km/h[74.93o]

D = 245 km[74.93o]

Answer 3

yes