^&%#*& mathematicians !
He flies on a HEADING of 030 east of north, NOT a bearing. You take a bearing on something, its direction from you. You sail or fly a compass HEADING.
anyway
East components are
90 sin 30 +150
=90 * (1/2) + 150
= 45 + 150
= 195 km east of start
A plane flies 90km on a bearing 030 degree and then flies 150km due east. How far east of the starting point is the plane?
8 answers
D = 90km[30o] + 150km[0o]
X = 90*Cos30 + 150 = 228 km.
Y = 90*sin30 = 45 km.
Tan A = Y/X = 45/228 = 0.19742
A = 11.17o
D=X/CosA = 228/Cos11.17=232 km[11.17o]
Dx = 232*cos11.17 = 227.998 km East of
starting point.
X = 90*Cos30 + 150 = 228 km.
Y = 90*sin30 = 45 km.
Tan A = Y/X = 45/228 = 0.19742
A = 11.17o
D=X/CosA = 228/Cos11.17=232 km[11.17o]
Dx = 232*cos11.17 = 227.998 km East of
starting point.
Henry,
The 30 degrees is from North (the y axis), not from east (the x axis as in math convention).
The 30 degrees is from North (the y axis), not from east (the x axis as in math convention).
Thanks! I thought it was 30o from the
x axis, because the problem didn't say
30o East of North.
x axis, because the problem didn't say
30o East of North.
Use a graph of f or some other method to determine what, if any, value to assign to f(a) to make f continuous at x = a. HINT [See Example 2.] (If there is no such value, enter NONE.)
f(x) =
x2 − 18x + 81
x − 9
; a = 9
f(x) =
x2 − 18x + 81
x − 9
; a = 9
I want the answer now
With diagrams
I don't understand why u got the answer