s
To solve this problem, we need to break down the initial velocity into its horizontal and vertical components. The horizontal component of the initial velocity is given by Vx = 22.2 cos(40°) = 16.97 m/s and the vertical component is given by Vy = 22.2 sin(40°) = 14.31 m/s.
The time taken for the ball to reach its maximum height can be calculated using the formula for vertical motion: Vy = Voy - gt. At the maximum height, Vy = 0, so 0 = 14.31 - 9.8t. Solving for t gives t = 1.46 seconds.
Since the total time in the air is twice the time it takes to reach the maximum height, the total time in the air is 2 * 1.46 = 2.92 seconds. Therefore, the correct answer is 2.92 seconds.
A placekicker kicks a football at initial speed of 22.2 m/s at an angle of 40.0°above the horizontal as shown in the figurer below.
Ignoring air resistance, calculate the total time the ball is in the air when it returns to its original height.
40y
I = Maximum height
a
"Ox
R = Range
00 s
14.3 s
17.0 s
2.92 s
1.46
1 answer
0 answers