viy=25sin45
vix=25cos45
a)let height be zero (y=0)
you can use y=vit+1/2at2, the use quadratic formula to find t
b)after you find t in part a...use x=vixt
x will be the horizontal distance of the ball
c) vfy=0m/s
use vfy^2=vi^2+2ay
y will be the maximum height
a=g=9.8m/s^2
..
bye...
A punter kicks a football at an angle of 45 degrees to the ground. The football has an initial velocity of 25 m/s, make a diagram and calculate:
a) How long was the football in the air?
b) How far does the football travel horizontally?
c) What is the maximum height of the football?
2 answers
a player kicks a football at an angle of 40 degrees with an initial speed of 48 ft/second. a second player standing at a distance of 100 ft from the first in the direction of the kick starts running to meet the ball at the instant it is kicked. how fast must he run in order to catch the ball before it hits the ground