a place kicker kick a ball 36m from a goal .which is 3.05 m high.it leaves the ground 20 m/s at an angle 53 to the horizontal.how much the ball clear or fall short of clearing the bar

Answer 1

Use d = d0 + v0t + (1/2)at^2

In the x direction:

x = x0 + v0t + (1/2)at^2

solve for t

Plug t into:

y = y0 + v0t + (1/2)at^2

y - 3.05 = The distance by which the ball will clear, or fall short of, the bar.

Answer 2

Velocity in x direction = v0cos(53)

Velocity in y direction = v0sin(53)