what three variables? All you have to do is see where the line intersects the parabola. Calling the first one h and d instead of y and x doesn't introduce any new variables. They are just names to describe the curve.
9x-10y=-14
y = (9x+14)/10
So, to see where they intersect, solve
-0.096(d-25)^2 +60 = (9x+14)/10
see
http://www.wolframalpha.com/input/?i=-0.096(x-25)%5E2+%2B60+%3D+0.1(9x%2B14)
A pilot of a downed airplane fires the emergency flare into the sky. The path of the flare is modelled by the equation h=-0.096(d-25)^2 +60 where h is the height of the flare in meters when its horizontal distance from where it was propelled is d meters. An emergency helicopter equipped with special binoculars has a line of sight to the spot where the flare was launched. The line of sight from the binocular is modelled by the equation 9x-10y=-14
Solve the system and give answers rounded to two decimal places. The line of sight from the binoculars spots the flare twice. How high was the flare closest to the ground when it was spotted the first time?
I have no idea how to do this as I only know how to solve with two different variables and not three. Do I sub x for d in the first equation? any help would be appreciated
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