Question

A pistol that fires a signal flare gives the flare an initial speed of 180m/s. Air resistance is ignored.
(a)If the flare is fired at an angle of 55° above the horizontal, what is the horizontal range?
(b)If the flare is fired at the same angle over the flat of sea tranquility on the moon where g=1.6m/s2, what is the horizontal range?
Pls help

Answer 1

Vo = 180m/s[55o].

a. Range = Vo^2*sin(2A)/g = 180^2*sin(110)/9.8 = 3107 m.

b. Same procedure as "a" except g = 1.6 m/s^2.